Hi there, Ive a doubt in finding circular convolution of two unequal sequences in MATLAB. Should the resultant length be equal to the highest of the given two vectors. Ive written a code for it but not sure about its result. Hope there would b some to help me. If neone have still optimised code, do post it. Thanks, Hari. x = [1 1 1 1 2 1]; h = [1 1 2 1]; Nx = length(x); Nh = length(h); N = max(Nx,Nh); x = [x zeros(1,NNx)]; h = [h zeros(1,NNh)]; m = 0:1:N1; M = mod(m,N) h = h(M+1) for n = 1:1:N m = n1; p = 0:1:N1; q = mod(pm,N) hm = h(q+1) H(n,:) = hm end Y = x*H' k = 0:N1; subplot(4,4,1); stem(k,Y); subplot(4,4,2); C = conv(x,h); K = 0:Nx+Nh4; 

circular conv
Started by ●March 28, 2003
Reply by ●March 31, 200320030331
That's right, in circular convolution the resultant length is the size
of the longest vector. You can test your results by using the circular convolution matrix, this link may help you: http://cnx.rice.edu/content/m10459/latest/ Regards, Claudio U. V.  Original Message  From: harima To: matlab Sent: Sunday, March 30, 2003 2:28 AM Subject: [matlab] circular conv Hi there, Ive a doubt in finding circular convolution of two unequal sequences in MATLAB. Should the resultant length be equal to the highest of the given two vectors. Ive written a code for it but not sure about its result. Hope there would b some to help me. If neone have still optimised code, do post it. Thanks, Hari. x = [1 1 1 1 2 1]; h = [1 1 2 1]; Nx = length(x); Nh = length(h); N = max(Nx,Nh); x = [x zeros(1,NNx)]; h = [h zeros(1,NNh)]; m = 0:1:N1; M = mod(m,N) h = h(M+1) for n = 1:1:N m = n1; p = 0:1:N1; q = mod(pm,N) hm = h(q+1) H(n,:) = hm end Y = x*H' k = 0:N1; subplot(4,4,1); stem(k,Y); subplot(4,4,2); C = conv(x,h); _____________________________________ Note: If you do a simple "reply" with your email client, only the author of this message will receive your answer. You need to do a "reply all" if you want your answer to be distributed to the entire group. _____________________________________ About this discussion group: To Join: To Post: To Leave: Archives: http://www.yahoogroups.com/group/matlab More DSPRelated Groups: http://www.dsprelated.com/groups.php3 