(@MrE)
I am looking forward to checking out Lattice Digital Filters. I just skimmed some information and ready to look deeper.Thank you,MrE
>>Be aware that the stability of a high pass filter is not trivial, while a low pass filter is usually behaving well.I've been learning about the high pass...
One of the issues I had encounter is that a single filter was insufficient due to limited precision. I was fortunate enough to read a Nigel's blog that explained...
The rounding errors are a strong possibility but unfortunately, I am constrained to single precision floats. I will look into adding a two sample average.Thank...
I recently read (somewhere) that you can get a better cutoff response by running you data through a filter multiple times. I am using cascading butterworth filters...
>> MichawelRW wrote: You've likely already found the issue with your script-file, but the
third argument to the "bilinear" function should be "Fs" not "1/Fs".The...
I used the same code base. https://www.dsprelated.com/showcode/214.phpI believe that if my method for determining the error rate were incorrect then it would have...
https://www.dsprelated.com/freebooks/filters/Four_Direct_Forms.htmlI've read about direct-form 1, direct-form 2, and transposed direct forms.I have ever so slight...
I've received a few responses of "No" unless there are other circumstance that permit this. I'm actually very grateful for those No responses because I pursue...
I'll go back and revisit the reference. I've used this to get an understanding of a subject out of my depth. It definitely has been helpful and thank you for...
I have been attempting to generate A & C weighted filters without success. I have tried multiple approaches but the simplest approach was to generate the coefficients...
After a lot of thinking and reading, I determined that I misunderstood the array output order of the ts2sos function. I converted the output order to the order...
I hadn't considered there may be something else occurring with b0. I'll check out your article. Unfortunately, I am math challenged (gleaning rather than consuming)...
Excellent. I thought I'd seen this before (dividing everything by b0).>>Assuming the routine does what's expected...You're absolutely right. I really dont...
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